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Knitting Design Math

03/08/07

Permalink 10:59:20 pm, by admin Email , 96 words, 264 views   English (US)
Categories: Amanda Knits and Designs, Designing, Knitting

Knitting Design Math

If I knit 3 inches with 2 balls of yarn doubled, how much yarn will it take to make a sleeveless sweater 24 inches long, considering that after 5 inches of work I will start decreasing on both sides and after 15 inches of work, I will split for the armholes? And how much extra yarn did that crazy-intensive 415 stitch I-cord cast on (thus, over 1600 stitches) take and how many more rows can that account for for the rest of the sweater?

Shoot, how many balls it needs it moot since I have 9 left.

So. How do I make this work?

Comments, Pingbacks:

Comment from: Jennifer [Visitor] Email · http://temptingyarns.blogspot.com
I don't think you can make it work. Splitting for the armholes doesn't take significantly less yarn (unless you are also making a v-neck). At worst, you need 16 more balls of yarn (5 more than you have). Depending on the details of the decreases and the armholes, perhaps 2 fewer than that - but I don't see how you will get by with only 9 more.
PermalinkPermalink 03/10/07 @ 04:24
Comment from: admin [Member] Email
It is a V-neck, but I did the math really specifically... I'd need two more balls of yarn and I can't find them at the store, so I'll rip it out and do something else.
PermalinkPermalink 03/11/07 @ 11:02

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